Optimal. Leaf size=134 \[ \frac{15 a \cos (c+d x)}{8 d}-\frac{5 a \cot ^3(c+d x)}{6 d}+\frac{5 a \cot (c+d x)}{2 d}+\frac{a \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac{a \cos (c+d x) \cot ^4(c+d x)}{4 d}+\frac{5 a \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac{15 a \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{5 a x}{2} \]
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Rubi [A] time = 0.126065, antiderivative size = 134, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 8, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.32, Rules used = {2838, 2592, 288, 321, 206, 2591, 302, 203} \[ \frac{15 a \cos (c+d x)}{8 d}-\frac{5 a \cot ^3(c+d x)}{6 d}+\frac{5 a \cot (c+d x)}{2 d}+\frac{a \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac{a \cos (c+d x) \cot ^4(c+d x)}{4 d}+\frac{5 a \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac{15 a \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{5 a x}{2} \]
Antiderivative was successfully verified.
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Rule 2838
Rule 2592
Rule 288
Rule 321
Rule 206
Rule 2591
Rule 302
Rule 203
Rubi steps
\begin{align*} \int \cos (c+d x) \cot ^5(c+d x) (a+a \sin (c+d x)) \, dx &=a \int \cos ^2(c+d x) \cot ^4(c+d x) \, dx+a \int \cos (c+d x) \cot ^5(c+d x) \, dx\\ &=-\frac{a \operatorname{Subst}\left (\int \frac{x^6}{\left (1-x^2\right )^3} \, dx,x,\cos (c+d x)\right )}{d}-\frac{a \operatorname{Subst}\left (\int \frac{x^6}{\left (1+x^2\right )^2} \, dx,x,\cot (c+d x)\right )}{d}\\ &=\frac{a \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac{a \cos (c+d x) \cot ^4(c+d x)}{4 d}+\frac{(5 a) \operatorname{Subst}\left (\int \frac{x^4}{\left (1-x^2\right )^2} \, dx,x,\cos (c+d x)\right )}{4 d}-\frac{(5 a) \operatorname{Subst}\left (\int \frac{x^4}{1+x^2} \, dx,x,\cot (c+d x)\right )}{2 d}\\ &=\frac{5 a \cos (c+d x) \cot ^2(c+d x)}{8 d}+\frac{a \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac{a \cos (c+d x) \cot ^4(c+d x)}{4 d}-\frac{(15 a) \operatorname{Subst}\left (\int \frac{x^2}{1-x^2} \, dx,x,\cos (c+d x)\right )}{8 d}-\frac{(5 a) \operatorname{Subst}\left (\int \left (-1+x^2+\frac{1}{1+x^2}\right ) \, dx,x,\cot (c+d x)\right )}{2 d}\\ &=\frac{15 a \cos (c+d x)}{8 d}+\frac{5 a \cot (c+d x)}{2 d}+\frac{5 a \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac{5 a \cot ^3(c+d x)}{6 d}+\frac{a \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac{a \cos (c+d x) \cot ^4(c+d x)}{4 d}-\frac{(15 a) \operatorname{Subst}\left (\int \frac{1}{1-x^2} \, dx,x,\cos (c+d x)\right )}{8 d}-\frac{(5 a) \operatorname{Subst}\left (\int \frac{1}{1+x^2} \, dx,x,\cot (c+d x)\right )}{2 d}\\ &=\frac{5 a x}{2}-\frac{15 a \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{15 a \cos (c+d x)}{8 d}+\frac{5 a \cot (c+d x)}{2 d}+\frac{5 a \cos (c+d x) \cot ^2(c+d x)}{8 d}-\frac{5 a \cot ^3(c+d x)}{6 d}+\frac{a \cos ^2(c+d x) \cot ^3(c+d x)}{2 d}-\frac{a \cos (c+d x) \cot ^4(c+d x)}{4 d}\\ \end{align*}
Mathematica [A] time = 1.36301, size = 138, normalized size = 1.03 \[ \frac{a \left (192 \cos (c+d x)-64 \cot (c+d x) \left (\csc ^2(c+d x)-7\right )+3 \left (16 \sin (2 (c+d x))-\csc ^4\left (\frac{1}{2} (c+d x)\right )+18 \csc ^2\left (\frac{1}{2} (c+d x)\right )+\sec ^4\left (\frac{1}{2} (c+d x)\right )-18 \sec ^2\left (\frac{1}{2} (c+d x)\right )+40 \left (3 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )-3 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )+4 c+4 d x\right )\right )\right )}{192 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.067, size = 221, normalized size = 1.7 \begin{align*} -{\frac{a \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{3\,d \left ( \sin \left ( dx+c \right ) \right ) ^{3}}}+{\frac{4\,a \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{3\,d\sin \left ( dx+c \right ) }}+{\frac{4\,a \left ( \cos \left ( dx+c \right ) \right ) ^{5}\sin \left ( dx+c \right ) }{3\,d}}+{\frac{5\,a \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) }{3\,d}}+{\frac{5\,\cos \left ( dx+c \right ) a\sin \left ( dx+c \right ) }{2\,d}}+{\frac{5\,ax}{2}}+{\frac{5\,ca}{2\,d}}-{\frac{a \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{4\,d \left ( \sin \left ( dx+c \right ) \right ) ^{4}}}+{\frac{3\,a \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{8\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}}}+{\frac{3\,a \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{8\,d}}+{\frac{5\,a \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{8\,d}}+{\frac{15\,\cos \left ( dx+c \right ) a}{8\,d}}+{\frac{15\,a\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.53686, size = 184, normalized size = 1.37 \begin{align*} \frac{8 \,{\left (15 \, d x + 15 \, c + \frac{15 \, \tan \left (d x + c\right )^{4} + 10 \, \tan \left (d x + c\right )^{2} - 2}{\tan \left (d x + c\right )^{5} + \tan \left (d x + c\right )^{3}}\right )} a - 3 \, a{\left (\frac{2 \,{\left (9 \, \cos \left (d x + c\right )^{3} - 7 \, \cos \left (d x + c\right )\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1} - 16 \, \cos \left (d x + c\right ) + 15 \, \log \left (\cos \left (d x + c\right ) + 1\right ) - 15 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.311, size = 562, normalized size = 4.19 \begin{align*} \frac{120 \, a d x \cos \left (d x + c\right )^{4} + 48 \, a \cos \left (d x + c\right )^{5} - 240 \, a d x \cos \left (d x + c\right )^{2} - 150 \, a \cos \left (d x + c\right )^{3} + 120 \, a d x + 90 \, a \cos \left (d x + c\right ) - 45 \,{\left (a \cos \left (d x + c\right )^{4} - 2 \, a \cos \left (d x + c\right )^{2} + a\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 45 \,{\left (a \cos \left (d x + c\right )^{4} - 2 \, a \cos \left (d x + c\right )^{2} + a\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) + 8 \,{\left (3 \, a \cos \left (d x + c\right )^{5} - 20 \, a \cos \left (d x + c\right )^{3} + 15 \, a \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{48 \,{\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.29321, size = 288, normalized size = 2.15 \begin{align*} \frac{3 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 8 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 48 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 480 \,{\left (d x + c\right )} a + 360 \, a \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) - 216 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \frac{192 \,{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 2 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 2 \, a\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{2}} - \frac{750 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 216 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 48 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 8 \, a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 3 \, a}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4}}}{192 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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